Some

http://agamecalledlife.blogspot.com/2006/01/below-average-students-guide-towards.html
http://agamecalledlife.blogspot.com/2005/08/useful-verbal-links.html
http://beatthegmat.blogspot.com/

http://in.rediff.com/getahead/2005/nov/15mcat.htm
http://www.ascenteducation.com/india-mba/iim/cat/questionbank/geometry.shtml

Triangle
http://en.wikipedia.org/wiki/Triangle
http://jwilson.coe.uga.edu/Texts.Folder/Halftri/trisect.html

7 ways to calculate the area of a triangle:
http://www.btinternet.com/~se16/hgb/triangle.htm

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Geometry
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Question 4 the day: February 11, 2003

The question for the day is based on some basic geometry concepts. A stairway 10ft high is such that each step accounts for half a foot upward and one-foot forward. What distance will an ant travel if it starts from ground level to reach the top of the stairway?
(1) 30 ft (2) 33 ft (3) 10 ft (4) 29 ft
Correct Answer - (4)
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Solution:
The ant moves 20 times upwards and only 19 times forward.
Therefore, the ant covers a distance of 20 * 0.5 = 10 feet when it moves upwardsAnd moves 19 * 1 = 19 feet forward
The total distance covered by the ant = 29 ft.
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Question 4 the day: April 11, 2003
The question for the day is from the topic of Analytical Geometry. Find the equation of a line whose intercepts are twice of the line 3x – 2y – 12 = 0
(1) 3x – 2y = 24 (2) 2x – 3y = 12 (3) 2x – 3y = 24 (4) None of these
Correct Answer - (1)
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Solution:
Put x = 0, then y = - 6
Therefore, y intercept is – 6
Put y = 0, then x = 4
Therefore, x intercept is 4
Hence the intercepts of the required line are 8 and – 12
Hence the equation of the line is (x/8) + (y/-12) = 1
-12x + 8y = -96
3x – 2y = 24.
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Question 4 the day: September 12, 2003
The question for the day is from the topic of Geometry. What is the measure of in radius of the triangle whose sides are 24, 7 and 25?
(1) 12.5 (2) 3 (3) 6 (4) None of these
Correct Answer - (2)
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Solution:
We know that for any triangle, area of the triangle = r*s, where r is the in radius and s is the semi perimeter
As the given triangle is a right angled triangle, area of the triangle = * 24 * 7 = 84 sq units.
S = semi perimeter =
Therefore, 84 = 28 * r
=> r = 84/28 = 3
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Question 4 the day: October 09, 2003
The question for the day is from the topic of Geometry. If ABC is a right angle triangle with angle A = 900 and 2s = a + b + c, where a > b > c where notations have their usual meanings, then which one of the following is correct?
(1) (s – b) (s – c) > s (s – a) (2) (s – a) (s – c) > s (s – b) (3) (s – a) (s – b) < a =" 5," b =" 4" c =" 3" s =" (a" 2 =" 12/2" polygon =" 1800." polygon =" 3600." polygon =" 14400." polygon =" 1440" 360 =" 1800" angles =" 180" n =" 1800" n =" 10." always =" 180o.Therefore," a =" 180"> A = 30o.No. of sides of a polygon = 360/EachExteriorAngle = 360/30 = 12 sides.
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Question 4 the day: May 13, 2003
The question for the day is from the topic of Geometry. Find the number of triangles in an octagon.
(1) 326 (2) 120 (3) 56 (4) Cannot be determined
Correct Answer - (3)
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Solution:
No. of triangles =nC3 where n is the no. of points.
Here n = 8 => number of triangles =8C3 = 56.
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To find the perimeter , just add all the sides. For regular polygons, the area is given by 1/2*A*S*n where 'n' is the number of sides of the polygon 'S' is the side of the polygon and 'A' is the apothem , the radius of the circle inscribed inside a polygon To find the area of an irregular polygon, check this link Hope this helps... Anu http://astronomy.swin.edu.au/~pbourke/geometry/polyarea/
vidya sri <sri_vidhu_sri@yahoo.com>
wrote:hai, i dont know how to find the area & perimeter of polygon like hexagon,hepatagon etc.. Well if u are talking about a regular polygon say hexagon or a pentagon then its easy u can divide ur polygon into equilateral triangles so a pentagon would have 5 equilateral triangles and a hexagon would have 6. then its easy is'nt itjust calculate the perimeter,area for the euilateral triangle multiplied by the number of traingle su have in ur ploygon. btw Area of eq triangle is (square root of 3)/4 X (a^2) where a is the side of the triangle.
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